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problems/009_problem_jnotebook.ipynb

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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#  Problem 9:\n",
+    "\n",
+    "[Euler Project #9](https://projecteuler.net/problem=9)\n",
+    "\n",
+    "\n",
+    "\n",
+    ">A Pythagorean triplet is a set of three natural numbers, a < b < c, for which,\n",
+    "a2 + b2 = c2\n",
+    "\n",
+    ">For example, 3^2 + 4^2 = 9 + 16 = 25 = 5^2.\n",
+    "\n",
+    ">There exists exactly one Pythagorean triplet for which a + b + c = 1000.\n",
+    "Find the product abc.\n",
+    "\n",
+    "\n",
+    "\n",
+    "---"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Reserved Space For Imports\n",
+    "---"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 1,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "import os\n",
+    "import pprint\n",
+    "import time  # Typically imported for sleep function, to slow down execution in terminal.\n",
+    "import typing\n",
+    "import decorators  # Typically imported to compute execution duration of functions.\n",
+    "import numpy\n",
+    "import pandas"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Reserved Space For Method Definition\n",
+    "---"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Can we describe a few approaches to solving this problem?\n",
+    "---"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "*Let's discuss a few ways to work through this, then select one to implement.*\n",
+    "\n",
+    " 1. Create a 2D array in which we can place each candidate series of integers.\\\n",
+    "  A column vector can also be created in which can store the product of each series.\\\n",
+    "  If we zip these arrays together, sort on the product column, we can identify the\\\n",
+    "  the maximum product and its associate string of integers.\n",
+    "<br/>\n",
+    "<br/>\n",
+    " 2. Create an array (of the specified length) to store a series of integers from the input\\\n",
+    "  number. Allow this to be an array that we use to compute the a product. It will shift as we\\\n",
+    "  slide along the input number. A second array of identical dimension, plus an additional place,\\\n",
+    "  could store the largest product, and the associated list of integers.  \n",
+    " "
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "### Let's try the first approach!"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### 1. a) Take in problem statement information."
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### 1. b) Build out the candidate array. "
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### 1. c) Cheat by using pandas to print out the maximum product and its associated series of integers. "
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 3",
+   "language": "python",
+   "name": "python3"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 3
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython3",
+   "version": "3.8.3"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 4
+}