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problems/001_problem.py

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+
+#  Problem 1:
+#  
+#  If we list all the natural numbers below 10 that 
+#  are multiples of 3 or 5, we get 3, 5, 6 and 9. 
+#  
+#  The sum of these multiples is 23.
+#  
+#  Find the sum of all the multiples of 3 or 5 below 1000.
+
+import functools
+import time
+
+def timer(f):
+	""" Decorator function to calculate compute time of passed function. """
+	
+	@functools.wraps(f)	
+	def wrapper_timer(*args,**kwargs):
+		
+		start_time = time.perf_counter()
+
+    	f(*args, **kwargs)
+    	
+    	end_time = time.perf_counter()
+    	run_time = end_time - start_time
+    	
+    	print("Finished {func.__name__!r} in {run_time:.4f} seconds...")
+
+    	return f
+
+	return wrapper_timer
+
+def check_divisibility(num, dict_multiples: dict) -> bool:
+	
+	dummy = 1
+	
+	for m in dict_multiples:
+		dummy *= num%m	
+	if dummy == 0:
+		return True
+	else:
+		return False
+
+@timer
+def main():
+
+	multiples = {3,5}
+	sumval = 0
+
+	for n in range(1000):
+		r = check_divisibility(n,multiples)
+		if r:
+			sumval += n
+
+	print(sumval)
+
+main()